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 化学反应N2+3H2=2NH3的能量变化如图所示,该反应的热化学方程式是

A.N2(g)+3H2(g)=2NH3(l);

ΔH=2(abc) kJ·mol-1

B.N2(g)+3H2(g)=2NH3(g);

ΔH=2(ba) kJ·mol-1

C.6ec8aac122bd4f6eN2(g)+6ec8aac122bd4f6eH2(g)=NH3(l);

ΔH=(bca) kJ·mol-1

D.6ec8aac122bd4f6eN2(g)+6ec8aac122bd4f6eH2((g)=NH3(g);ΔH=(ab) kJ·mol-1

 

答案:
 A
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